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What is the moment at joint F, in a case where there is no side sway and the member CF is along the axis of symmetry while a UDL of W kN/m is applied all along the length BD as shown in the figure?

What is the moment at joint F, in a case where there is no side sway and the member CF is along the axis of symmetry while a UDL of W kN/m is applied all along the length BD as shown in the figure? Correct Answer 0

By taking the advantages of symmetry and using intuition, the deflected shape of the given structure is drawn as shown below:

From the deflected shape following can be concluded:

1. At joint C vertical deflection is zero.

2. At joint C slope is zero.

3. Since there is no sway in frame implies that horizontal displacement of joint C is zero.

Based on above, joint C behaves like rigid joint and Joint F is already fixed and there is no transverse loading in between joint C and F hence, the entire member CF behaves like a rigid bar and hence no bending will be induced throughout the entire span of CF because rigid bar can only rotate or translate, it cannot bend or deform.

∴ The bending moment developed at joint F is Zero.

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