Square roots of −i , where i = √−1, are

Square roots of −i , where i = √−1, are Correct Answer <span class="math-tex">\(cos\left(-\frac{\pi}{4}\right)+i\:sin\left(-\frac{\pi}{4}\right), cos\left(\frac{3\pi}{4}\right)+i\:sin\left(\frac{3\pi}{4}\right)\)</span>

We know that,

i = eiπ/2

⇒ -i = e-iπ/2

⇒ √-i = ± 1/2 = ± e-iπ/4

= ±

= cos (π/4) - i sin (π/4);  - cos (π/4) + i sin (π/4)

= cos (-π/4) + i sin (-π/4);  cos (3π/4) + i sin (3π/4) 

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