Square roots of −i , where i = √−1, are
Square roots of −i , where i = √−1, are Correct Answer <span class="math-tex">\(cos\left(-\frac{\pi}{4}\right)+i\:sin\left(-\frac{\pi}{4}\right), cos\left(\frac{3\pi}{4}\right)+i\:sin\left(\frac{3\pi}{4}\right)\)</span>
We know that,
i = eiπ/2
⇒ -i = e-iπ/2
⇒ √-i = ± 1/2 = ± e-iπ/4
= ±
= cos (π/4) - i sin (π/4); - cos (π/4) + i sin (π/4)
= cos (-π/4) + i sin (-π/4); cos (3π/4) + i sin (3π/4)
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Feb 20, 2025