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There are two huts of two brothers each on the opposites sides of a medium sized pond. Each brother has to use 12 stones in the pond to visit each other’s hut by crossing the pond. These stones are numbered serially using numbers one to twelve. A dragon fly is jumping on these stones as follows; every minute it jumps to the fifth stone from where it started. Thus if it jumps from the fourth stone it would go to the ninth stone, from the ninth stone it would go to the second stone and so on. Select the option that indicates the number of stones on which this dragon fly would be resting if it stops jumping at the 36th minute if it starts jumping from the stone that is numbered two.

There are two huts of two brothers each on the opposites sides of a medium sized pond. Each brother has to use 12 stones in the pond to visit each other’s hut by crossing the pond. These stones are numbered serially using numbers one to twelve. A dragon fly is jumping on these stones as follows; every minute it jumps to the fifth stone from where it started. Thus if it jumps from the fourth stone it would go to the ninth stone, from the ninth stone it would go to the second stone and so on. Select the option that indicates the number of stones on which this dragon fly would be resting if it stops jumping at the 36th minute if it starts jumping from the stone that is numbered two. Correct Answer 2

Given:

There are 12 stones numbered serially from 1 to 12 in the pond.

A dragon fly jumps to the 5th stone every minute from where it started.

Calculation:

Time(in min) Initial Stone Number Final Stone Number
1 2 7
2 7 12
3 12 5
4 5 10
5 10 3
6 3 8
7 8 1
8 1 6
9 6 11
10 11 4
11 4 9  
12 9 2
13 2 7

As we see in the above table in 12th minute the dragon fly will jump from stone 9 to stone 2 and rest.

⇒ Next on 24th min again this process will repeat.

⇒ At the 36th minute, the dragon fly will be resting on stone no 2.

Hence, option 2 is correct.

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