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The sum of the digits of a two-digit number is 10. When the digits are reversed, the number decreases by 54. Find the reversed number.

The sum of the digits of a two-digit number is 10. When the digits are reversed, the number decreases by 54. Find the reversed number. Correct Answer 28

Let the number be 10x + y.

x + y = 10      ----(1)

(10 x + y) – (10 y + x) = 54      ----(2)

Solving (1) and (2), x = 8, y = 2

∴ Changed number = 10y + x = 28

Mistake Points

The original number = 82

But is the question asked for the reverse number,

So that is equal to 28. 

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