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Mr. John is conducting elevator experiments. Bobby stands on a weigh scale and reads the scale while ascending and descending the building. Bobby’s mass is 80 kg. He notices that the scale readings depend on what the elevator is doing. Angular velocity of hour hand watch is double than that of Earth’s rotation. What is the scale reading when John accelerates upward at 0.40 m/s2?

Mr. John is conducting elevator experiments. Bobby stands on a weigh scale and reads the scale while ascending and descending the building. Bobby’s mass is 80 kg. He notices that the scale readings depend on what the elevator is doing. Angular velocity of hour hand watch is double than that of Earth’s rotation. What is the scale reading when John accelerates upward at 0.40 m/s2? Correct Answer 816 N

Given mass = 80 kg and acceleration = 0.40 m/s2

Fnet = ma = (80 kg) × (0.4 m/s2) = 32 N, up

So the up force (Fnorm) is 32 N greater than Fgrav.

Fgrav = mg = 784 N, down since g = 9.8

Therefore, Fnorm = 816 N.

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