A flexible wire is used to make triangles. When this wire is folded from its middle, a triangle of 9 cm perimeter can be formed. If an equilateral triangle is formed with the given length of the wire such that it has the maximum possible perimeter, what is the area of triangle formed?
A flexible wire is used to make triangles. When this wire is folded from its middle, a triangle of 9 cm perimeter can be formed. If an equilateral triangle is formed with the given length of the wire such that it has the maximum possible perimeter, what is the area of triangle formed? Correct Answer 15.57 cm<sup>2</sup>
Let the length of wire is L
The wire is folded from its middle then the perimeter is half of the length of the wire,
⇒ L/2 = 9 cm
⇒ L = 18 cm
The largest equilateral triangle that can be formed using this length of wire is a triangle which has each side of 6 cm
∴ Area of an equilateral is ((√3)/4) × side2 = (1.73 × 36)/4 = 1.73 × 9 = 15.57 cm2
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Feb 20, 2025




