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When 1-liter alcohol is added to the 20-liter mixture of alcohol and water, the quantity of alcohol becomes 50% less than that of water in the mixture. Find the initial ratio of alcohol and water in the mixture?

When 1-liter alcohol is added to the 20-liter mixture of alcohol and water, the quantity of alcohol becomes 50% less than that of water in the mixture. Find the initial ratio of alcohol and water in the mixture? Correct Answer 3 ∶ 7

Let the initial quantity of alcohol in the mixture = x liter

So, the initial quantity of water in the mixture = (20 – x) liters

According to the question ∶

(x + 1) = (20 – x) × 50/100

(x + 1) = (20 – x) × 1/2

2x + 2 = 20 – x

3x = 18

x = 6

The initial quantity of alcohol in the mixture = 6 liters

The initial quantity of water in the mixture = 20 – 6 = 14 liters

Required ratio = 6 ∶ 14 = 3 ∶ 7

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