There are three tanks A, B, and C of capacity 545 L, 411 L, and 727 L respectively which are filled using a jar of a certain capacity. When tanks A, B, and C are filled using the jar, then 5 L, 6 L, and 7 L respectively of tanks remain empty, then what is the capacity of the jar?

There are three tanks A, B, and C of capacity 545 L, 411 L, and 727 L respectively which are filled using a jar of a certain capacity. When tanks A, B, and C are filled using the jar, then 5 L, 6 L, and 7 L respectively of tanks remain empty, then what is the capacity of the jar? Correct Answer 45 L

Calculation:

Filled quantity of tank A = 545 – 5 = 540 L

Filled quantity of tank B = 411 – 6 = 405 L

Filled quantity of tank C = 727 – 7 = 720 L

⇒ The capacity of jar = HCF of the filled quantity of three tanks = HCF of 540, 405 and 720

= 45

∴ The capacity of jar = 45 liters

Related Questions

Jar A comprises a mixture of milk and water in the ratio of 3 : 2 respectively. Another mixture of milk and water is added to jar A and the ratio of milk and water in the resultant mixture changes. What was the initial quantity of mixture present in Jar A? I. The ratio of milk and water in the mixture that was added to Jar A was 2 : 1 respectively. II. The ratio of the new quantities of milk and water in Jar A was 8 : 5 respectively. The quantity of water in the mixture added to jar A was 6 litre.