Consider the following statements: Statement I: Median can be computed even when the end intervals of a frequency distribution are open. Statement II: Median is a positional average. Which one of the following is correct in respect of the above statements?

Consider the following statements: Statement I: Median can be computed even when the end intervals of a frequency distribution are open. Statement II: Median is a positional average. Which one of the following is correct in respect of the above statements? Correct Answer Both Statement I and Statement II are true and Statement II is the correct explanation of Statement I

Median is the magnitude of the middle term when all the terms in the series are arranged in order of their magnitudes (either ascending or descending). Hence, the median is a positional average, where the middlemost value of the series represents the whole series.

Due to this property, the median is not dependent on the magnitude of all the terms, i.e., if a term smaller than the median is replaced by another term that is also smaller than the median, then the median remains unchanged. So, the median is not influenced by the extreme values of the distribution. Hence, the median is the best-suited measure in case of an open-ended frequency distribution.

∴ Both Statement I and Statement II are true and Statement II is the correct explanation of Statement I

Related Questions

Statement I): The arithmetic mean is an all purpose average. Statement II): Median and mode are called positional averages. In the context of the above two statements, which one of the following codes is correct?