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How many 4 digit even numbers can be formed by 2, 0, 1, 3, and 5 when repetition is allowed ?

How many 4 digit even numbers can be formed by 2, 0, 1, 3, and 5 when repetition is allowed ? Correct Answer 200

Calculation:

For even numbers: unit placed number should be multiple of 2 or zero

1st digit can be one of 2,1, 3,5 = (4 choices)

2nd digit can be one of 0,1, 2,3,5 = (5 choices)

3rd digit can be one of 0,1, 2,3,5 = (5 choices)

4th digit can be one of 0, 2 = (2 choices)

So, Total numbers = 4 × 5 × 5 × 2 = 200

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