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Select the option that is true regarding the following two statements labeled Assertion (A) and Reason (R). Assertion (A): Whenever we measure an electrical signal, there are chances of over current which leads to overheating of the meter. In such cases, the meter can be protected by using a semiconductor diode of suitable rating. Reason (R): As soon as the diode is short-circuited, the meter current is diverted through the diode. As a result, the meter is being protected from excess heating.

Select the option that is true regarding the following two statements labeled Assertion (A) and Reason (R). Assertion (A): Whenever we measure an electrical signal, there are chances of over current which leads to overheating of the meter. In such cases, the meter can be protected by using a semiconductor diode of suitable rating. Reason (R): As soon as the diode is short-circuited, the meter current is diverted through the diode. As a result, the meter is being protected from excess heating. Correct Answer Both A and R are true and R is the correct explanation of A

Assertion Explanation - When we measure an electrical signal there very often may be a chance of over current through the meter. This may be due to following reasons.

  • The meter may be connected wrongly to the circuit.
  • The rating of the meter is selected wrongly for the measurement.
  • Occurrences of over current in the circuit itself during measurement.


Over current causes overheating in the meter which may ultimately lead to a permanent damage to the meter. The reasons of the over current cannot be avoided 100% although it is convenient to protect the meter from the effect of over current. This is done by using semiconductor diode of suitable rating.

Reason Explanation - Whenever a meter is connected in the circuit to measure an electrical signal, there must be a voltage drop across it. If the current through the meter is increased beyond safety limit, the voltage drop also crosses the rated limit. Suppose the rated voltage drop limit of the meter is 0.6 volt. Now, let us connect a diode across the meter, whose forward barrier voltage is 0.6 volt. Now, if due to excess current through the meter, if the voltage drop across the meter becomes more than 0.6 volt, the diode becomes short-circuited, since this excess voltage also appears across the diode.

4. 

When v ≥ 0.6 → diode will be short circuted.

Since current flows through the lowest Resistance path, where diode is s. c. R = 0 so whole current will pass through diode and NOW we can protect our meter from overcurrent.

Since both statement (A) and (R) is true and (R) is correct explanation of (A).So option(3) is correct.

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