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Shruti went to a candy store. She took 29 candies (of the same size but different colors) out of a jar and went home. The candies were such that there were 6 red candies, 3 yellow candies, 13 orange candies, and 7 blue candies. When she reached home, her brother also asked for candy. She draws a candy randomly without looking into the bag. What is the probability of getting neither red nor orange candy?

Shruti went to a candy store. She took 29 candies (of the same size but different colors) out of a jar and went home. The candies were such that there were 6 red candies, 3 yellow candies, 13 orange candies, and 7 blue candies. When she reached home, her brother also asked for candy. She draws a candy randomly without looking into the bag. What is the probability of getting neither red nor orange candy? Correct Answer 10/29

Given:

Total number of candies = 29

Red candies = 6

Yellow candies = 3

Orange candies = 13

Blue candies = 7

Formula used:

Probability of an event = Number of outcomes that make an event / Total number of outcomes of the experiment (when outcomes are equally likely)

Calculations:

Number of outcomes that make an event = Candy is neither red nor orange

Candy is neither red nor orange = Candy is either yellow or blue

Number of outcomes that make an event = 3 + 7

⇒ 10

Total number of outcomes = 29

Probability = 10/29

∴ The probability of getting neither red nor orange candy is 10/29

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