Find the equation of the line parallel to the line whose equation is y = 6x + 7 and whose y-intercept is 8.

Find the equation of the line parallel to the line whose equation is y = 6x + 7 and whose y-intercept is 8. Correct Answer y = 6x + 8

The equation of the given line is y = 6x + 7

Standard equation of line is y = mx + c where m is slope.

Slope of the parallel lines are same.

The equation of a line parallel to this line will be y = 6x + k

Given: y-intercept of the required line is 8

Put x = 0 and y = 8 in y = 6x + k

8 = 0 + k

k = 8

Therefore, the equation of the required line is y = 6x + 8

Related Questions

The letters P, Q, R, S, T and U are to be placed one per vertex on a regular convex hexagon, but not necessarily in the same order. Consider the following statements: The line segment joining R and S is longer than the line segment joining P and Q. The line segment joining R and S is perpendicular to the line segment joining P and Q. The line segment joining R and U is parallel to the line segment joining T and Q. Based on the above statements, which one of the following options is CORRECT?
In a plane, line X is perpendicular to line Y and parallel to line Z; line U is perpendicular to both lines V and W; line X is perpendicular to line V. Which one of the following statements is correct?