AB and AC are the two tangents to a circle, whose radius is 6 cm. If ∠BAC = 60°, then what is the value (in cm) of √(AB2 + AC2)?

AB and AC are the two tangents to a circle, whose radius is 6 cm. If ∠BAC = 60°, then what is the value (in cm) of √(AB2 + AC2)? Correct Answer 6√6

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As given ∠BAC = 60° and we know that from an external point, all the tangents to the circle are of equal length so AB = AC.

∴ ∠BAO = ∠OAC = 60°/2 = 30°

Since ΔABO and ΔACO are right angle triangles;

∴ AB = AC = 6/tan30° = 6√3

∴ √(AB2 + AC2) = √(108 + 108) = 6√6 cm

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