Given below are three quantities named 1, 2 and 3. Based on the given information, you have to determine the relationship between the three quantities. You should use the given data and knowledge of Mathematics to choose between the possible answer. Quantity 1: A and B are competing in a game called, "Get a six". The first one who gets a six on throwing a dice wins. If A starts, what is the probability of B's winning. Quantity 2: When 1 is added to the numerator of a fraction, the fraction becomes 150% of the previous number. If three is added to denominator, the number becomes 1/4. Find the number. Quantity 3: Increase in average weight of group. Average of 12 people is 12.6 kg, 2 people are added to the group. Average weight of new people is 15.3 kg.

Given below are three quantities named 1, 2 and 3. Based on the given information, you have to determine the relationship between the three quantities. You should use the given data and knowledge of Mathematics to choose between the possible answer. Quantity 1: A and B are competing in a game called, "Get a six". The first one who gets a six on throwing a dice wins. If A starts, what is the probability of B's winning. Quantity 2: When 1 is added to the numerator of a fraction, the fraction becomes 150% of the previous number. If three is added to denominator, the number becomes 1/4. Find the number. Quantity 3: Increase in average weight of group. Average of 12 people is 12.6 kg, 2 people are added to the group. Average weight of new people is 15.3 kg. Correct Answer Quantity 1 > Quantity 2 > Quantity 3

Quantity 1:

Probability of getting a six = 1/6

Probability of not getting a six = 5/6

For B to win, A must not get a six and B must.

Probability = (5/6) × (1/6) + (5/6) × (5/6) × (5/6) × (1/6) + (5/6) × (5/6) × (5/6) × (5/6) × (5/6) × (1/6) + .......

This becomes a Geometric progression of infinite terms.

a = 5/6 × 1/6 = 5/36

r = 5/6 × 5/6 = 25/36 = 0.69

Sum of infinite terms = a/(1 - r) = (5/36)/(1 - 25/36) = 5/11

Quantity 2:

let the fraction be p/q.

Now, according to condition,

(p + 1)/q = 150% of p/q

On solving, p = 2

Now, 2/(q + 3) = 1/4

q + 3 = 8

q = 5

Fraction is p/q = 2/5 = 0.4

Quantity 3:

Excess weight than the average = (15.3 - 12.6) × 2 = 5.4 kg

Now, this excess weight will be divided in 14 people of the new group.

Increase in weight of every member = 5.4/14 = 0.39 kg.

Hence, Quantity 1 > Quantity 2 > Quantity 3

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