A circle of radius of 10 cm and another circle whose radius is 20% less than that of first circle, intersect at the points P and Q. If length of PQ is 20% more than the radius of first circle. The distance between the centers of the circle is x cm. What is value of x?
A circle of radius of 10 cm and another circle whose radius is 20% less than that of first circle, intersect at the points P and Q. If length of PQ is 20% more than the radius of first circle. The distance between the centers of the circle is x cm. What is value of x? Correct Answer 13.3
Radius of the first circle OP = 10 cm
Radius of the other circle O’P = 10 × = 8 cm
Length of PQ = 10 × = 12 cm
As we know, PM = PQ/2, PM = 6 cm
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In ΔPO’M
By using Pythagoras Theorem
⇒ (O’P)2 = (O’M)2 + (PM)2
⇒ 82 = (O’M)2 + 62
⇒ O’M = √28 cm
In ΔPOM
By using Pythagoras Theorem
⇒ (OP)2 = (OM)2 + (PM)2
⇒ 102 = (OM)2 + 62
⇒ OM = 8 cm
⇒ O’O = OM + O’M = √28 + 8 = 5.3 + 8 = 13.3 cm