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If the gold foil is replaced by any other metal foil whose atomic number is larger than the atomic number of the gold and rest all properties are same as that of gold then the distance of closest approach in Rutherford’s alpha scattering will be -

If the gold foil is replaced by any other metal foil whose atomic number is larger than the atomic number of the gold and rest all properties are same as that of gold then the distance of closest approach in Rutherford’s alpha scattering will be - Correct Answer Less than that in gold foil

CONCEPT:

  • Rutherford’s Model of the Atom:
    • He bombarded the beam of alpha particles on a very thin gold foil.
    • While bombarding he observes the number of scattering of particles –
      • Most of the particles passed either un-deviated or with very small deviation.
      • Some deviated by large angles
      • 1 out of 8000 was deflected by more than 90° 

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EXPLANATION:

  • When the alpha particles are bombarded on the gold foil then the nucleus of the god foil repel the alpha beam and some of the alpha particle reach to a point which is most close to the nucleus. This distance is called closest distance.
  • If the atomic number of the atom is increased then the positive charge on the nucleus will increases and the force of repulsion on the alpha particles beam will increases.
  • Due to the increase in force of repulsion, the closest approach will decrease. Thus it will be less than that in case of gold foil. So option 1 is correct.

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