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Find the equation of line whose is passing through the point (2, - 3) and the slope of line is perpendicular to the line passing through the point (3, 6) and (-4, 4)?

Find the equation of line whose is passing through the point (2, - 3) and the slope of line is perpendicular to the line passing through the point (3, 6) and (-4, 4)? Correct Answer 7x + 2y = 8

Formula used:

Line of equation; (y - y1) = m(x - x1)

Slope of perpendicular line = - 1/m

Calculation:

Slope of the line passing through (3, 6) and (-4, 4) = (4 - 6)/(-4 - 3) = 2/7

∴ The slope of the line perpendicular to that line = - 1/(2/7) = -7/2

So, Equation of line passing through (2, - 3):

⇒ (y + 3) = -7/2(x - 2)

⇒ 2y + 6 = -7x + 14

⇒ 7x + 2y = (14 - 6)

⇒ 7x + 2y = 8

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