Nine individuals - Z, Y, X, W, V, U, T, S and R - are the only candidates, who can serve on three committees-K1, K2 and K3, and each candidate should serve on exactly one of the committees. Committee K1 should consist of exactly one member more than committee K2. It is possible that there are no members in committee K3. Among Z, Y and X none can serve on committee 10. Among W, V and U none can serve on committee K2. Among T, S and R none can serve on committee K3. In case committee K2 is served by T and Z only, how many of the nine individuals should serve on committee K3?
Nine individuals - Z, Y, X, W, V, U, T, S and R - are the only candidates, who can serve on three committees-K1, K2 and K3, and each candidate should serve on exactly one of the committees. Committee K1 should consist of exactly one member more than committee K2. It is possible that there are no members in committee K3. Among Z, Y and X none can serve on committee 10. Among W, V and U none can serve on committee K2. Among T, S and R none can serve on committee K3. In case committee K2 is served by T and Z only, how many of the nine individuals should serve on committee K3? Correct Answer 4
Nine individuals -: Z, Y, X, W, V, U, T, S and R
Three committees-K1, K2 and K3,
1) Each candidate should serve on exactly one of the committees.
2) Among Z, Y and X none can serve on committee K1.
2) Among W, V and U none can serve on committee K2.
3) Among T, S and R none can serve on committee K3
4) It is possible that there are no members in committee K3
5) In case committee K2 is served by T and Z
|
Committees |
Individuals who can serve |
Individuals who cannot serve |
|
K1 |
|
Z, Y, X |
|
K2 |
T, Z |
W, V, U |
|
K3 |
|
T, S, R |
K1 should consist of exactly one member more than committee K2.
So, K1 is served by three members as K2 is served by two members only.
So, remaining individuals will serve committee K3.
Remaining persons = 9 – (2 + 3)
= 9 – 5
= 4
Hence, ‘4’ is the correct answer.