Six boys A, B, C, D, E and F play a game of cards. Each has a pack of 10 cards. F borrows 2 cards from A and gives away 5 to C who in turn gives 3 to B while B gives 6 to D who passes on 1 to E. Then the number of cards possessed by D and E is equal to the number of cards possessed by
Six boys A, B, C, D, E and F play a game of cards. Each has a pack of 10 cards. F borrows 2 cards from A and gives away 5 to C who in turn gives 3 to B while B gives 6 to D who passes on 1 to E. Then the number of cards possessed by D and E is equal to the number of cards possessed by Correct Answer B, C and F
Initially, each has a pack of 10 cards.
| A | B | C | D | E | F |
| 10 | 10 | 10 | 10 | 10 | 10 |
F borrows 2 cards from A and gives away 5 to C who in turn gives 3 to B
| A | B | C | D | E | F |
| 8 | 13 | 12 | 10 | 10 | 7 |
B gives 6 to D who passes on 1 to E
| A | B | C | D | E | F |
| 8 | 7 | 12 | 15 | 11 | 7 |
Total cards possessed by D and E = 15 + 11 = 26
This number is same as the total cards possessed by B, C and F.
Hence, option 2 is the correct answer.
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Feb 20, 2025