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The perimeter of two squares are 72 cm and 64 cm. Then find the area of a third square whose perimeter is equal to the sum of the perimeter of the these squares.

The perimeter of two squares are 72 cm and 64 cm. Then find the area of a third square whose perimeter is equal to the sum of the perimeter of the these squares. Correct Answer 1156 cm<sup>2</sup>

Given:

The perimeter of the two squares are 72 cm and 64 cm.

Formula used:

The perimeter of the square = 4 × side

Area of square = (side)2

Calculation:

Sum of perimeter of given square = 72 + 64 = 136 cm

Let the side of the third square be 's'

Now, the perimeter of the third square = 4s

And, 4s = 136 cm

⇒ s = 136/4 = 34 cm

Area of third square = (34)2 = 1156 cm2

∴ The area of the third square is 1156 cm2.

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