ABCDEF is a regular hexagon. Find the value of ∠DBC and ∠FED.

ABCDEF is a regular hexagon. Find the value of ∠DBC and ∠FED. Correct Answer 30°, 120°

Given:

ABCDEF is a regular hexagon

Calculation:

/n

⇒ Angle of hexagon = (4 × 180°)/6 = 120°

⇒ ∠FED = 120°

In a triangle BCD,

⇒ BC = DC (∵ regular hexagon)

⇒ ∠CDB = ∠DBC

⇒ ∠BCD = 120° 

⇒ ∠BCD + ∠DBC + ∠CDB = 180°

(∵ regular hexagon has equal internal angles)

⇒ 120° + 2∠DBC = 180°

⇒ ∠DBC = 30°

∴ Required answers are ∠DBC = 30° and ∠FED = 120°.

Related Questions

ABCDEF is a regular hexagon inscribed inside a circle. If the shortest diagonal of the hexagon is of length 3 units, what is the area of the shaded region?