The arithmetic mean between two numbers is A and their geometric mean is G. Then the numbers are
The arithmetic mean between two numbers is A and their geometric mean is G. Then the numbers are Correct Answer <span class="math-tex">\(A \pm \sqrt {{A^2} - {G^2}} \)</span>
Given:
Arithmetic mean = A
Geometric mean = G
Explanation:
Let the numbers be x and y
⇒ (x + y)/2 = A --(1)
⇒ √ (xy) = G
⇒ y = G2/x
Put the value of y in equation (1)
⇒ (x + (G2/x))/2 = A
⇒ x2 + G2 = 2Ax
⇒ x2 + G2 - 2Ax = 0
⇒ x = A ± √ (A2 - G2)
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Feb 20, 2025