The arithmetic mean between two numbers is A and their geometric mean is G. Then the numbers are

The arithmetic mean between two numbers is A and their geometric mean is G. Then the numbers are Correct Answer <span class="math-tex">\(A \pm \sqrt {{A^2} - {G^2}} \)</span>

Given:

Arithmetic mean = A

Geometric mean = G

Explanation:

Let the numbers be x and y

⇒ (x + y)/2 = A   --(1)

⇒ √ (xy) = G

⇒ y = G2/x         

Put the value of y in equation (1)

⇒ (x + (G2/x))/2 = A

⇒ x2 + G2 = 2Ax

⇒ x2 + G- 2Ax = 0

⇒ x = A ± √ (A2 - G2)

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