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Five boys and five girls sit on a round ride. Two girls sat adjacent to each other. No two boys sit adjacent to each other. Not more than two girls sit on adjacent seats. Find the total different combinations possible.

Five boys and five girls sit on a round ride. Two girls sat adjacent to each other. No two boys sit adjacent to each other. Not more than two girls sit on adjacent seats. Find the total different combinations possible. Correct Answer The case is not possible

Given:

Five boys and five girls sit on a round ride

Two girls sat adjacent to each other

No two boys sit adjacent to each other

Not more than two girls sit on adjacent seats

Concept:

To find the total number of ways of arranging, first the selection has to be done. Then, number of ways of arranging has to be found out.

Calculation:

Two girls sat adjacent to each other

Not more than two girls sit on adjacent seats

⇒ They are both sitting adjacent to one boy

No two boys sit adjacent to each other

⇒ They both sit adjacent to a girl

Now, four adjacent seats remain and three boys remain

It is not possible to arrange these three boys such that no two boys sit adjacent to each other

Hence, zero ways

∴ This case is not possible

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