0.001M NaOH দ্রবণের pH কত ?
A
12
B
3
C
14
D
11
Correct Answer: 11
NaOH ↔️ Na+ + OH-[OH-] = [NaOH] = 0.001MPOH = -log[OH-] = -log(0.001) = 3pH = 14 - POH = 14 - 3 = 11