0.001M KOH দ্রবণের pH কত ?
A
3
B
2
C
11
D
12
Correct Answer: 11
KOH ↔️ K+ + OH- [OH-] = [KOH] = 0.001M POH = -log[OH-] = -log(0.001) = 3 pH = 14 - POH = 14 - 3 = 11