0.001 M KOH দ্রবণের pH কত ?
A
1
B
2
C
11
D
12
Correct Answer: 11
KOH ↔️ K+ + OH-[OH-] = [KOH] = 0.001MPOH = -log[OH-] = -log(.001) = 3pH = 14 - POH = 14 - 3 = 11