Related Questions

A pile of length ‘L’ carrying a uniformly distributed load ‘W’ per metre length is suspended at two points, the maximum, B.M. at the centre of the pile or at the points of suspension, is
ক $$\frac{{{\text{WL}}}}{8}$$
খ $$\frac{{{\text{W}}{{\text{L}}^2}}}{{24}}$$
গ $$\frac{{{\text{W}}{{\text{L}}^2}}}{{47}}$$
ঘ $$\frac{{{\text{W}}{{\text{L}}^2}}}{{16}}$$
In testing a pile by load test, pile platform is loaded with one and half times the design load and a maximum settlement is noted. The load is gradually removed and the consequent rebound is measured. For a safe pile, the net settlement (i.e. total settlement minus rebound) per tonne of test load should not exceed
ক 10 mm
খ 15 mm
গ 20 mm
ঘ 25 mm
To ensure that the hogging bending moment at two points of suspension of a pile of length L equals the sagging moment at its centre, the distances of the points of suspension from either end, is
ক 0.107 L
খ 0.207 L
গ 0.307 L
ঘ 0.407 L
When a uniformly distributed load, longer than the span of the girder, moves from left to right, then the maximum bending moment at mid section of span occurs when the uniformly distributed load occupies
ক Less than the left half span
খ Whole of left half span
গ More than the left half span
ঘ Whole span
The natural frequency of free transverse vibrations due to uniformly distributed load acting over a simply supported shaft is (where $$\delta {\text{S}}$$ = Static deflection of simply supported shaft due to uniformly distributed load)
ক $$\frac{{0.4985}}{{\sqrt {\delta {\text{S}}} }}$$
খ $$\frac{{0.5615}}{{\sqrt {\delta {\text{S}}} }}$$
গ $$\frac{{0.571}}{{\sqrt {\delta {\text{S}}} }}$$
ঘ $$\frac{{0.6253}}{{\sqrt {\delta {\text{S}}} }}$$
The maximum deflection of a fixed beam of length '$$l$$' carrying a total load 'W' uniformly distributed over the whole length is
ক $$\frac{{{\text{W}}{l^3}}}{{48{\text{E}}I}}$$
খ $$\frac{{{\text{W}}{l^3}}}{{96{\text{E}}I}}$$
গ $$\frac{{{\text{W}}{l^3}}}{{192{\text{E}}I}}$$
ঘ $$\frac{{{\text{W}}{l^3}}}{{384{\text{E}}I}}$$
The shear force of a cantilever beam of length $$l$$ carrying a uniformly distributed load of w per unit length is __________ at the fixed end.
ক Zero
খ $$\frac{{{\text{w}}l}}{4}$$
গ $$\frac{{{\text{w}}l}}{2}$$
ঘ $${\text{w}}l$$
The bending moment of a cantilever beam of length '$$l$$' and carrying a uniformly distributed load of 'w' per unit length is __________ at the fixed end.
ক $$\frac{{{\text{w}}l}}{4}$$
খ $$\frac{{{\text{w}}l}}{2}$$
গ $${\text{w}}l$$
ঘ $$\frac{{{\text{w}}{l^2}}}{2}$$
The shear force diagram of a cantilever beam of length ‘l’ and carrying a uniformly distributed load of w per unit length will be
ক A right angled triangle
খ An isosceles triangle
গ An equilateral triangle
ঘ A rectangle
For a circular slab carrying a uniformly distributed load, the ratio of the maximum negative to maximum positive radial moment, is
ক 1
খ 2
গ 3
ঘ 5

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