The speed of a DC shunt motor is required to be more than full load speed . This is possible by-

A reducing the field current
B decreasing the armature current
C increasing the armature current
D None of the above

Correct Answer: reducing the field current

Bissoy MCQ
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Related Questions

The speed of a D.C. shunt motor is required to be more than full load speed. This is possible by
A Reducing the field current
B Decreasing the armature current
C Increasing the armature current
D Increasing the excitation current
If a D.C. shunt motor is working at full load and if shunt field circuit suddenly opens
A This will make armature to take heavy current, possibly burning it
B This will result in excessive speed, possibly destroying armature due to excessive centrifugal stresses
C Nothing will happen to motor
D Motor will come to stop
The speed of a D.C. shunt motor more than its full-load speed can be obtained by
A Decreasing the field current
B Increasing the field current
C Decreasing the armature current
D Increasing the armature current
If a D.C. shunt motor is working at no load and if shunt field circuit suddenly opens
A Nothing will happen to the motor
B This will make armature to take heavy current, possibly burning it
C This will result in excessive speed, possibly destroying armature due to excessive centrifugal stresses
D Motor will run at very slow speed
If the speed of a D.C. shunt motor is increased, the back e.m.f. of the motor will
A Increase
B Decrease
C Remain same
D Become zero
As the load is increased the speed of D.C. shunt motor will
A Reduce slightly
B Increase slightly
C Increase proportionately
D Remains unchanged
If the field of a D.C. shunt motor gets opened while motor is running
A The speed of motor will be reduced %
B The armature current will reduce
C The motor will attain dangerously high speed 1
D The motor will continue to run at constant speed
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B power factor as well as armature current will increase
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