0.001M NaOH এর pH কত?
A
12
B
10
C
13
D
11
Correct Answer: 11
NaOH ↔️ Na+ + OH- [OH-] = [NaOH] = 0.001M POH = -log[OH-] = -log(.001) = 3 pH = 14 - POH = 14 - 3 = 11