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If x is the average (arithmetic mean) of m and 9, y is the average of 2m and 15, and z is the average of 3m and 18, What is the average of x, y and z in terms of m?

If x is the average (arithmetic mean) of m and 9, y is the average of 2m and 15, and z is the average of 3m and 18, What is the average of x, y and z in terms of m? Correct Answer m+7

x = m + 92⇒2x = m + 9.......(i)y = 2m + 152⇒2y = 2m + 15........(ii)z = 3m + 182⇒2z = 3m + 18.......(iii)(i) + (ii) + (iii)⇒2x + 2y + 2z = m + 9 + 2m + 15 + 3m + 18⇒2(x + y + z) = 6m + 42⇒x + y + z = 3m + 21⇒x + y + z3 = m + 7

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