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If the average (arithmetic mean) of a,b, and c is 40, what is the average (arithmetic mean) of (3a+10), (3b+10), and (3c+10)?

If the average (arithmetic mean) of a,b, and c is 40, what is the average (arithmetic mean) of (3a+10), (3b+10), and (3c+10)? Correct Answer 130

( a + b + c)/3 = 40 a + b + c = 120 Again, { (3a + 10) + ( 3b + 10) + ( 3c + 10)}/3 = ( 3a + 10 + 3b + 10 + 3c + 10o/3 = 3( a + b + c) + 30 /3 = 3×120 + 30/ 3 = 130

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