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Given the probabilities P(A) = 0.3 and P(B) = 0.2, what is the probability of the union P(A ? B) if A and B are mutually exclusive? If A and B are independent? If B is a subset of A?

Given the probabilities P(A) = 0.3 and P(B) = 0.2, what is the probability of the union P(A ? B) if A and B are mutually exclusive? If A and B are independent? If B is a subset of A? Correct Answer .5, 0.44, 0.3

(D) If A and B are mutually exclusive, then P(A ? B) = 0, and so P(A ? B) = 0.3 + 0.2 - 0 = 0.5. If A and B are independent, then P(A ? B) = PP(B), and so P(A ? B) = 0.3 + 0.2 - (0.3)(0.2) = 0.44. If B is a subset of A, then A ? B = A, and so P(A ? B) = P = 0.3.

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