A solution is prepared by dissolving 30.0 grams of Ni(NO3)2 in enough water to make 250 mL of solution. What is the molarity of this solution?

A solution is prepared by dissolving 30.0 grams of Ni(NO3)2 in enough water to make 250 mL of solution. What is the molarity of this solution? Correct Answer 0.656 mol/L

(B) Molarity is the moles of solute in each liter of solution; molarity = mol solute/L solution

Related Questions