Comment on the behaviour of the following C code?
#include int main(){ int i = 2; i = i++ + i; printf("%d\n", i);}

Comment on the behaviour of the following C code?

#include <stdio.h>int main(){ int i = 2; i = i++ + i; printf("%d\n", i);}
Correct Answer = operator is not a sequence point

Related Questions

Comment on the following 2 C programs.
#include  //Program 1int main(){ int a; int b; int c;}#include  //Program 2int main(){ int a; { int b; } { int c; }}