The interchange factor for radiation heat transfer from surface 'x' to surface 'y' in case of an infinite parallel planes with emis-sivities $${\varepsilon _{\text{x}}}$$ & $${\varepsilon _{\text{y}}}$$ is given by

The interchange factor for radiation heat transfer from surface 'x' to surface 'y' in case of an infinite parallel planes with emis-sivities $${\varepsilon _{\text{x}}}$$ & $${\varepsilon _{\text{y}}}$$ is given by Correct Answer $$\frac{{{\varepsilon _{\text{x}}} + {\varepsilon _{\text{y}}}}}{{{\varepsilon _{\text{x}}} + {\varepsilon _{\text{y}}} - {\varepsilon _{\text{x}}} \cdot {\varepsilon _{\text{y}}}}}$$

Related Questions

Consider the 5 × 5 matrix \[{\text{A}} = \left[ {\begin{array}{*{20}{c}} 1&2&3&4&5 \\ 5&1&2&3&4 \\ 4&5&1&2&3 \\ 3&4&5&1&2 \\ 2&3&4&5&1 \end{array}} \right
For infinite parallel planes having emis-sivities $${{\varepsilon _1}}$$ & $${{\varepsilon _2}}$$, the interchange factor for radiation from surface 1 to surface 2 is given by
An infinite parallel planes with emissivities e1 and e2, the interchange factor for radiation from surface 1 to surface 2 is given by
At the interface between two linear dielectrics (with dielectric constants $${{\varepsilon _1}}$$ and $${{\varepsilon _2}}$$), the electric field lines bend, as shown in the figure. Assume that there are no free charges at the interface. The ratio $$\frac{{{\varepsilon _1}}}{{{\varepsilon _2}}}$$ is
Electromagnetic Theory mcq question image