If H and d are the water depth and drop in the bed level at a Sarda fall, the width B of the trapezoidal crest, is given by
A
$${\text{B}} = 0.22\sqrt {{\text{H}} + {\text{d}}} $$
B
$${\text{B}} = 0.33\sqrt {{\text{H}} + {\text{d}}} $$
C
$${\text{B}} = 0.44\sqrt {{\text{H}} + {\text{d}}} $$
D
$${\text{B}} = 0.55\sqrt {{\text{H}} + {\text{d}}} $$
Correct Answer: $${\text{B}} = 0.55\sqrt {{\text{H}} + {\text{d}}} $$
