Related Questions

As compared to crest of the normal portion of the weir, the crest of the under sluice portion of weir is kept at
A lower level
B higher level
C same level
D any of the above depending on the design
The discharge passing over an ogee spillway is given by (where, L is effective length of spillway crest and H is the total head over the spillway crest including velocity head.)
A $${\text{CL}}{{\text{H}}^{\frac{3}{2}}}$$
B $${\text{CH}}{{\text{L}}^{\frac{3}{2}}}$$
C $${\text{CL}}{{\text{H}}^{\frac{5}{2}}}$$
D $${\text{CL}}{{\text{H}}^{\frac{1}{2}}}$$
For smooth entry of water in a canal, the angle between head regulator and water is generally kept
A 80°
B 90°
C 110°
D 120°
A swimming pool is initially filled to a depth of 96 inches. After 2 weeks, the depth has decreased to9212 inches. Assuming that the depth decreased at a constant rate, after how many days would the water depth have reached 9334 inches?
A 3
B 9
C 7
D 6
The ratio of the discharge over a trapezoidal crest to a rectangular crest of Sarda falls of identical parameters, is
A 1.084
B 1.074
C 1.064
D 1.054
A weir is said to be narrow-crested weir, if the width of the crest of the weir is __________ half the height of water above the weir crest.
A Equal to
B Less than
C More than
D None of these
A weir is said to be broad crested weir, if the width of the crest of the weir is ________ half the height of water above the weir crest.
A Equal to
B Less than
C More than
D None of these
A Zener voltage regulator will cease to act as a voltage regulator if Zener current becomes ___________
A Less than load current
B Zero
C More than load current
D None of the above
In a barrage, the crest level is kept
A Low with large gates
B High with large gates
C High with no gates
D Low with no gates
If H and d are the water depth and drop in the bed level at a Sarda fall, the width B of the trapezoidal crest, is given by
A $${\text{B}} = 0.22\sqrt {{\text{H}} + {\text{d}}} $$
B $${\text{B}} = 0.33\sqrt {{\text{H}} + {\text{d}}} $$
C $${\text{B}} = 0.44\sqrt {{\text{H}} + {\text{d}}} $$
D $${\text{B}} = 0.55\sqrt {{\text{H}} + {\text{d}}} $$

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