A square hole is punched out of a circular lamina, the diagonal of the square being the radius of the circle. If ‘r’ is the radius of the circle, the C.G. of the remainder from the corner of the square on the circumference will be
A
$$\frac{{{\text{r}}\left( {\pi + 0.25} \right)}}{{\pi - 0.5}}$$
B
$$\frac{{{\text{r}}\left( {\pi - 0.5} \right)}}{{\pi + 0.25}}$$
C
$$\frac{{{\text{r}}\left( {\pi - 0.25} \right)}}{{\pi - 0.5}}$$
D
$$\frac{{{\text{r}}\left( {\pi + 0.25} \right)}}{{\pi + 0.5}}$$
Correct Answer: $$\frac{{{\text{r}}\left( {\pi - 0.25} \right)}}{{\pi - 0.5}}$$
