For a simple pendulum, the period of one oscillation is
A
$$2\pi \sqrt {\frac{l}{{2{\text{g}}}}} $$
B
$$2\pi \sqrt {\frac{{2{\text{g}}}}{l}} $$
C
$$2\pi \sqrt {\frac{l}{{\text{g}}}} $$
D
$$2\pi \sqrt {\frac{{\text{g}}}{{2l}}} $$
Correct Answer: $$2\pi \sqrt {\frac{l}{{\text{g}}}} $$