The equivalent length of a simple pendulum which gives the same frequency as a compound pendulum is

A $$\frac{{\text{h}}}{{{\text{k}}_{\text{G}}^2 + {{\text{h}}^2}}}$$
B $$\frac{{{\text{k}}_{\text{G}}^2 + {{\text{h}}^2}}}{{\text{h}}}$$
C $$\frac{{{{\text{h}}^2}}}{{{\text{k}}_{\text{G}}^2 + {{\text{h}}^2}}}$$
D $$\frac{{{\text{k}}_{\text{G}}^2 + {{\text{h}}^2}}}{{{{\text{h}}^2}}}$$

Correct Answer: $$\frac{{{\text{k}}_{\text{G}}^2 + {{\text{h}}^2}}}{{\text{h}}}$$

Related Questions

The equivalent length of a simple pendulum which gives the same frequency as compound pendulum is
The length of a simple pendulum which gives the same frequency as the compound pendulum, is
The periodic time of one oscillation for a simple pendulum is (where $$l$$ = Length of the pendulum.)
The frequency of oscillation of a compound pendulum is

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