Related Questions

When the bearing is subjected to large fluctuations of load and heavy impacts, the bearing characteristic number should be _________ the bearing modulus.
A 10 times
B 5 times
C 15 times
D 20 times
The frictional torque transmitted in a flat pivot bearing, considering uniform wear, is (where μ = Coefficient of friction, W = Load over the bearing and R = Radius of bearing surface)
A $$\frac{1}{2}$$μWR
B $$\frac{2}{3}$$μWR
C $$\frac{3}{4}$$μWR
D μWR
If ‘H’ is the height of wall between centers of supports, then the effective height of wall where concrete floors have a bearing on wall irrespective of the direction of span will be
A 0.75 H
B 0.85 H
C 1.0 H
D 1.5 H
In the plate loading test for determining the bearing capacity of soil, the size of square bearing plate should be
A less than 300 mm
B between 300 mm and 750 mm
C between 750 mm and 1 m
D greater than 1 m
A ladder is resting against a vertical wall and its bottom is 2.5 m away from the wall. If it slips 0.8 m down the wall, then its bottom will move away from the wall by 1.4 m. What is the length of the ladder?
A 6.2 m
B 6.5 m
C 6.8 m
D \7.5 m
Direct load carrying capacity of a brick masonry wall standing freely as against when it supports RC slab will be
A More
B Less
C The same in both the cases
D 100%
If p = bearing pressure on projected bearing area, Z = absolute viscosity of lubricant and N = speed of journal, then the bearing characteristic number is given by
A $$\frac{{{\text{ZN}}}}{{\text{p}}}$$
B $$\frac{{\text{p}}}{{{\text{ZN}}}}$$
C $$\frac{{\text{Z}}}{{{\text{pN}}}}$$
D $$\frac{{\text{N}}}{{{\text{Zp}}}}$$
Gold is 19 times as heavy as water and Copper is 9 times as heavy as water. Calculate the ratio in which these two metals should be mixed so that the mixture is 15 times as heavy as water.
A 40
B 41
C 42
D 43
In a journal bearing, the load on the bearing is __________ to the axis of the journal.
A Parallel
B Perpendicular
C Both A and B
D None of these
If A is the area of the foundation of a retaining wall carrying a load W and retaining earth of weight 'w' per unit volume, the minimum depth (h) of the foundation from the free surface of the earth, is
A $${\text{h}} = \frac{{\text{W}}}{{{\text{Aw}}}}\left$$
B $${\text{h}} = \frac{{\text{W}}}{{{\text{Aw}}}}\left$$
C $${\text{h}} = \frac{{\text{W}}}{{{\text{Aw}}}}{\left^2}$$
D $${\text{h}} = \sqrt {\frac{{\text{W}}}{{{\text{Aw}}}}} {\left^2}$$

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