Related Questions

The natural frequency of free transverse vibrations due to uniformly distributed load acting over a simply supported shaft is (where $$\delta {\text{S}}$$ = Static deflection of simply supported shaft due to uniformly distributed load)
A $$\frac{{0.4985}}{{\sqrt {\delta {\text{S}}} }}$$
B $$\frac{{0.5615}}{{\sqrt {\delta {\text{S}}} }}$$
C $$\frac{{0.571}}{{\sqrt {\delta {\text{S}}} }}$$
D $$\frac{{0.6253}}{{\sqrt {\delta {\text{S}}} }}$$
The natural frequency of free transverse vibrations due to a point load acting over a simply supported shaft is equal to (where $$\delta $$ = Static deflection of a simply supported shaft due to the point load)
A $$\frac{{0.4985}}{{\sqrt \delta }}$$
B $$\frac{{0.5615}}{{\sqrt \delta }}$$
C $$\frac{{0.571}}{{\sqrt \delta }}$$
D $$\frac{{0.6253}}{{\sqrt \delta }}$$
Design of R.C.C. cantilever beams, is based on the resultant force at
A Fixed end
B Free end
C Mid span
D Mid span and fixed support
A simply supported beam A carries a point load at its mid span. Another identical beam B carries the same load but uniformly distributed over the entire span. The ratio of the maximum deflections of the beams A and B, will be
A $$\frac{2}{3}$$
B $$\frac{3}{2}$$
C $$\frac{5}{8}$$
D $$\frac{8}{5}$$
The simply supported beam 'A' of length '$$l$$' carries a central point load 'W'. Another beam 'B' is loaded with a uniformly distributed load such that the total load on the beam is 'W'. The ratio of maximum deflections between beams 'A' and 'B' is
A $$\frac{5}{8}$$
B $$\frac{8}{5}$$
C $$\frac{5}{4}$$
D $$\frac{4}{5}$$
The bending moment in the center of a simply supported beam carrying a uniformly distributed load of w per unit length is
A Zero
B $$\frac{{{\text{w}}{l^2}}}{2}$$
C $$\frac{{{\text{w}}{l^2}}}{4}$$
D $$\frac{{{\text{w}}{l^2}}}{8}$$
The shear force at the ends of a simply supported beam carrying a uniformly distributed load of w per unit length is
A Zero at its both ends
B $${\text{w}}l$$ at one end and $$ - {\text{w}}l$$  at the other end
C $$\frac{{{\text{w}}l}}{2}$$ at one end and $$ - \frac{{{\text{w}}l}}{2}$$  at the other end
D $$\frac{{{\text{w}}{l^2}}}{2}$$ at one end and $$ - \frac{{{\text{w}}{l^2}}}{2}$$  at the other end
The shear force diagram for a simply supported beam carrying a uniformly distributed load of w per unit length, consists of
A One right angled triangle
B Two right angled triangles
C One equilateral triangle
D Two equilateral triangles
In a simply supported beam carrying a uniformly distributed load w per unit length, the point of contraflexure
A Lies in the center of the beam
B Lies at the ends of the beam
C Depends upon the length of beam
D Does not exist
The maximum bending moment of a simply supported beam of span $$l$$ and carrying a point load W at the center of beam, is
A $$\frac{{{\text{W}}l}}{4}$$
B $$\frac{{{\text{W}}l}}{2}$$
C $${\text{W}}l$$
D $$\frac{{{\text{W}}{l^2}}}{4}$$

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