Related Questions

The natural frequency of free transverse vibrations due to uniformly distributed load acting over a simply supported shaft is (where $$\delta {\text{S}}$$ = Static deflection of simply supported shaft due to uniformly distributed load)
A $$\frac{{0.4985}}{{\sqrt {\delta {\text{S}}} }}$$
B $$\frac{{0.5615}}{{\sqrt {\delta {\text{S}}} }}$$
C $$\frac{{0.571}}{{\sqrt {\delta {\text{S}}} }}$$
D $$\frac{{0.6253}}{{\sqrt {\delta {\text{S}}} }}$$
The simply supported beam 'A' of length '$$l$$' carries a central point load 'W'. Another beam 'B' is loaded with a uniformly distributed load such that the total load on the beam is 'W'. The ratio of maximum deflections between beams 'A' and 'B' is
A $$\frac{5}{8}$$
B $$\frac{8}{5}$$
C $$\frac{5}{4}$$
D $$\frac{4}{5}$$
A simply supported beam which carries a uniformly distributed load has two equal overhangs. To have maximum B.M. produced in the beam least possible, the ratio of the length of the overhang to the total length of the beam, is
A 0.207
B 0.307
C 0.407
D 0.508
The bending moment in the center of a simply supported beam carrying a uniformly distributed load of w per unit length is
A Zero
B $$\frac{{{\text{w}}{l^2}}}{2}$$
C $$\frac{{{\text{w}}{l^2}}}{4}$$
D $$\frac{{{\text{w}}{l^2}}}{8}$$
The shear force at the ends of a simply supported beam carrying a uniformly distributed load of w per unit length is
A Zero at its both ends
B $${\text{w}}l$$ at one end and $$ - {\text{w}}l$$  at the other end
C $$\frac{{{\text{w}}l}}{2}$$ at one end and $$ - \frac{{{\text{w}}l}}{2}$$  at the other end
D $$\frac{{{\text{w}}{l^2}}}{2}$$ at one end and $$ - \frac{{{\text{w}}{l^2}}}{2}$$  at the other end
The shear force diagram for a simply supported beam carrying a uniformly distributed load of w per unit length, consists of
A One right angled triangle
B Two right angled triangles
C One equilateral triangle
D Two equilateral triangles
The shear force in the center of a simply supported beam carrying a uniformly distributed load of ‘w’ per unit length, is
A Zero
B $$\frac{{{\text{w}}{l^2}}}{2}$$
C $$\frac{{{\text{w}}{l^2}}}{4}$$
D $$\frac{{{\text{w}}{l^2}}}{8}$$
The bending moment diagram for a simply supported beam carrying a uniformly distributed load of ‘w’ per unit length, will be
A A horizontal line
B A vertical line
C An inclined line
D A parabolic curve
A simply supported beam A carries a point load at its mid span. Another identical beam B carries the same load but uniformly distributed over the entire span. The ratio of the maximum deflections of the beams A and B, will be
A $$\frac{2}{3}$$
B $$\frac{3}{2}$$
C $$\frac{5}{8}$$
D $$\frac{8}{5}$$
A simply supported beam 'A' of length l, breadth b, and depth d carries a central point load W. Another beam 'B' has the same length and depth but its breadth is doubled. The deflection of beam 'B' will be __________ as compared to beam 'A'.
A One-fourth
B One-half
C Double
D Four times

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