The power absorbed (in watts) in overcoming the viscous resistance of a footstep bearing is
A
$$\frac{{\mu {\pi ^3}{{\text{N}}^2}{{\text{R}}^2}}}{{1800{\text{t}}}}$$
B
$$\frac{{\mu {\pi ^3}{{\text{N}}^2}{{\text{R}}^4}}}{{1800{\text{t}}}}$$
C
$$\frac{{\mu {\pi ^3}{{\text{N}}^2}{{\text{R}}^2}}}{{3600{\text{t}}}}$$
D
$$\frac{{\mu {\pi ^3}{{\text{N}}^2}{{\text{R}}^4}}}{{3600{\text{t}}}}$$
Correct Answer: $$\frac{{\mu {\pi ^3}{{\text{N}}^2}{{\text{R}}^4}}}{{1800{\text{t}}}}$$
