Moment of inertia of a triangular section of base (b) and height (h) about an axis through its base, is
A
$$\frac{{{\text{b}}{{\text{h}}^3}}}{4}$$
B
$$\frac{{{\text{b}}{{\text{h}}^3}}}{8}$$
C
$$\frac{{{\text{b}}{{\text{h}}^3}}}{{12}}$$
D
$$\frac{{{\text{b}}{{\text{h}}^3}}}{{36}}$$
Correct Answer: $$\frac{{{\text{b}}{{\text{h}}^3}}}{{12}}$$