The moment of inertia of a triangular section (height h, base b) about its base, is
A
$$\frac{{{\text{b}}{{\text{h}}^2}}}{{12}}$$
B
$$\frac{{{{\text{b}}^2}{\text{h}}}}{{12}}$$
C
$$\frac{{{\text{b}}{{\text{h}}^3}}}{{12}}$$
D
$$\frac{{{{\text{b}}^3}{\text{h}}}}{{12}}$$
Correct Answer: $$\frac{{{\text{b}}{{\text{h}}^3}}}{{12}}$$