A cube subjected to three mutually perpendicular stress of equal intensity p expenses a volumetric strain

A cube subjected to three mutually perpendicular stress of equal intensity p expenses a volumetric strain Correct Answer $$\frac{{3{\text{p}}}}{{\text{E}}} \times \left( {1 - \frac{2}{{\text{m}}}} \right)$$

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When a body is subjected to biaxial stress i.e. direct stresses ($${\sigma _{\text{x}}}$$) and ($${\sigma _{\text{y}}}$$) in two mutually perpendicular planes accompanied by a simple shear stress ($${\tau _{{\text{xy}}}}$$ ), then maximum shear stress is
When a body is subjected to biaxial stress i.e. direct stresses (σx) and (σy) in two mutually perpendicular planes accompanied by a simple shear stress (τxy), then maximum normal stress is
When a body is subjected to biaxial stress i.e. direct stresses (σx) and (σy) in two mutually perpendicular planes accompanied by a simple shear stress (τxy), then minimum normal stress is