Related Questions

The maximum shear stress developed in a beam of rectangular section is __________ the average shear stress.
A Equal to
B $$\frac{4}{3}$$ times
C 1.5 times
D Twice
The maximum shear stress developed in a beam of circular section is __________ the average shear stress.
A Equal to
B $$\frac{4}{3}$$ times
C 1.5 times
D Twice
The ratio of maximum shear stress to average shear stress of a circular beam, is
A $$\frac{2}{3}$$
B $$\frac{3}{2}$$
C $$\frac{3}{4}$$
D $$\frac{4}{3}$$
A closely coiled helical spring is acted upon by an axial force. The maximum shear stress developed in the spring is $$\tau $$. The half of the length of the spring if cut off and the remaining spring is acted upon by the same axial force. The maximum shear stress in the spring in new condition will be
A $$\frac{\tau }{2}$$
B $$\tau $$
C $$2\tau $$
D $$4\tau $$
According to maximum shear stress failure criterion, yielding in material occurs, when the maximum shear stress is equal to __________ times the yield stress.
A 0.5
B 2
C $$\sqrt 2 $$
D $$\sqrt {\frac{3}{2}} $$
The bending moment ‘M’ and a torque ‘T’ is applied on a solid circular shaft. If the maximum bending stress equals to maximum shear stress developed, then ‘M’ is equal to
A $$\frac{{\text{T}}}{2}$$
B 1T
C 2T
D 4T
When a beam of rectangular cross-section of width b and depth d, is subjected to a shear force F, the maximum shear stress induced will be
A $$\frac{{\text{F}}}{{{\text{bh}}}}$$
B $$\frac{{{\text{3F}}}}{{{\text{2bh}}}}$$
C $$\frac{{{\text{2F}}}}{{{\text{bh}}}}$$
D $$\frac{{{\text{4F}}}}{{{\text{bh}}}}$$
When a circular beam of diameter d is subjected to a shear force F, the maximum shear stress induced will be
A $$\frac{{4{\text{F}}}}{{\pi {{\text{d}}^2}}}$$
B $$\frac{{{\text{6F}}}}{{\pi {{\text{d}}^2}}}$$
C $$\frac{{{\text{8F}}}}{{\pi {{\text{d}}^2}}}$$
D $$\frac{{{\text{16F}}}}{{3\pi {{\text{d}}^2}}}$$
When a body is subjected to biaxial stress i.e. direct stresses ($${\sigma _{\text{x}}}$$) and ($${\sigma _{\text{y}}}$$) in two mutually perpendicular planes accompanied by a simple shear stress ($${\tau _{{\text{xy}}}}$$ ), then maximum shear stress is
A $$\frac{1}{2}\sqrt {{{\left( {{\sigma _{\text{x}}} - {\sigma _{\text{y}}}} \right)}^2} + 4\tau _{{\text{xy}}}^2} $$
B $$\frac{1}{2}\sqrt {{{\left( {{\sigma _{\text{x}}} + {\sigma _{\text{y}}}} \right)}^2} + 4\tau _{{\text{xy}}}^2} $$
C $$\sqrt {{{\left( {{\sigma _{\text{x}}} - {\sigma _{\text{y}}}} \right)}^2} + \tau _{{\text{xy}}}^2} $$
D $$\sqrt {{{\left( {{\sigma _{\text{x}}} + {\sigma _{\text{y}}}} \right)}^2} + \tau _{{\text{xy}}}^2} $$
When a body is subjected to a direct tensile stress ($${\sigma _{\text{x}}}$$) in one plane accompanied by a simple shear stress ($${\tau _{{\text{xy}}}}$$ ), the maximum shear stress is
A $$\frac{{{\sigma _{\text{x}}}}}{2} + \frac{1}{2}\sqrt {\sigma _{\text{x}}^2 + 4\tau _{{\text{xy}}}^2} $$
B $$\frac{{{\sigma _{\text{x}}}}}{2} - \frac{1}{2}\sqrt {\sigma _{\text{x}}^2 + 4\tau _{{\text{xy}}}^2} $$
C $$\frac{{{\sigma _{\text{x}}}}}{2} + \frac{1}{2}\sqrt {\sigma _{\text{x}}^2 - 4\tau _{{\text{xy}}}^2} $$
D $$\frac{1}{2}\sqrt {\sigma _{\text{x}}^2 + 4\tau _{{\text{xy}}}^2} $$

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