The minimum periodic time of a compound pendulum is
A
$$\frac{1}{{2\pi }}\sqrt {\frac{{{{\text{k}}_{\text{G}}}}}{{\text{g}}}} $$
B
$$\frac{1}{{2\pi }}\sqrt {\frac{{{\text{2}}{{\text{k}}_{\text{G}}}}}{{\text{g}}}} $$
C
$$2\pi \sqrt {\frac{{{{\text{k}}_{\text{G}}}}}{{\text{g}}}} $$
D
$$2\pi \sqrt {\frac{{{\text{2}}{{\text{k}}_{\text{G}}}}}{{\text{g}}}} $$
Correct Answer: $$2\pi \sqrt {\frac{{{\text{2}}{{\text{k}}_{\text{G}}}}}{{\text{g}}}} $$